苹果maccms v10二次更新只替换某一个资源图片

某个资源站倒闭了,但是以前采集了很多他的资源,导致现在很多图片都不显示了.再以后的采集过程中不希望所有的图片都被重新替换,怎么才能只更新这个倒闭了的资源站的图片呢.这里做个记录
找到applicationcommonmodelCollect.php这个文件的第839行左右(版本不同可能行数也不同).

if (strpos(',' . $config['uprule'], 'j')!==false && (substr($info["vod_pic"], 0, 4) == "http" || empty($info['vod_pic']) ) && $v['vod_pic']!=$info['vod_pic'] ) {  	$tmp = $this->syncImages($config['pic'],$v['vod_pic'],'vod');  	$update['vod_pic'] = (string)$tmp['pic'];  	$msg =$tmp['msg'];  }  

替换为

if(strstr($info['vod_pic'],"vlwx.com")==true){  	if (strpos(',' . $config['uprule'], 'j')!==true && (substr($info["vod_pic"], 0, 4) == "http" || empty($info['vod_pic']) ) && $v['vod_pic']!=$info['vod_pic'] ) {  		$tmp = $this->syncImages($config['pic'],$v['vod_pic'],'vod');  		$update['vod_pic'] = (string)$tmp['pic'];  		$msg =$tmp['msg'];  		}  }else{  	if (strpos(',' . $config['uprule'], 'j')!==false && (substr($info["vod_pic"], 0, 4) == "http" || empty($info['vod_pic']) ) && $v['vod_pic']!=$info['vod_pic'] ) {  		$tmp = $this->syncImages($config['pic'],$v['vod_pic'],'vod');  		$update['vod_pic'] = (string)$tmp['pic'];  		$msg =$tmp['msg'];  		}  }  

其中的的vlwx.com换成失效图片的关键词即可!